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15+6y^2=231
We move all terms to the left:
15+6y^2-(231)=0
We add all the numbers together, and all the variables
6y^2-216=0
a = 6; b = 0; c = -216;
Δ = b2-4ac
Δ = 02-4·6·(-216)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*6}=\frac{-72}{12} =-6 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*6}=\frac{72}{12} =6 $
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